I'm not sure you understand JSONP. The code you have here doesn't make sense: The callback you're supplying is "3", not the name of a global JavaScript function The PHP side isn't generating a call to the JSON callback.
I'm not sure you understand JSONP. The code you have here doesn't make sense: The callback you're supplying is "3", not the name of a global JavaScript function. The PHP side isn't generating a call to the JSON callback.
When your browser request the mysubdomain.comoj.com/jsoncall.php?jsonC... url, it's make an HTTP request to the php page. When the http server send you a response it just contain "3" as body, wich is not valid javascript and nothing happen. Moreover, if you want to create a php page that build a dinamic javascript you have to first tell the browser that you're sending a javascript file by using the header("Content-Type: textt/javascript"); directive before print anything to screen.
Last but not least...you're not doing a jSONP call at all :).
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