Kirchoff's rules, current, voltage, circuit problem-- help?

I will try: At node 1, I will define +'ve as current coming into the node and negative as current leaving the node: I get at node 1: I1 = I2 + I3 (based on the direction of the arrows already drawn on there) I get at node 2: I3 = I4 Applying KVL which says that the sum of all voltages around the loop = 0 For Loop 1 : 12 - V1 - V2 - V5 = 0 For Loop 2: V2 - V3 - V4 = 0 I will now try to go thru getting Requivalent: Resistor R3 and R4 are in series so they sum up to: 3.3K + 4.7K = 8.0K The 8.0K is in parallet with 10K so the equivalent resistance is: 1/Req = 1/8K + 1/10K ----> Req = 4.444K Now R1, the Req and R5 are in series so we can add them to get: Requivalent = 1K + 4.444K + 2K = 7.444K So now we have 12V power supply going across 7.444K resistor. Current = I1 = V/Requiv = 12/7.444K = 1.6119 mA I think you can take it from here - thank you and please check my work.

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