A/(x+4)+(Bx+C)/(x²+3) (Ax²+3A+Bx²+Cx+4Bx+4C)/(x²+3)(x+4) Ax²+Bx²=5x² A+B=5 A=5-B Cx+4Bx=28x C+4B=28 C=28-4B 3A+4C=-6 plug in A=5-B and C=28-4B 3(5-B)+4(28-4B)=-6 15-3B+112-16B=-6 -19B=-133 B=7 A=5-B A=-2 C=28-4B C=0 A/(x+4)+(Bx+C)/(x²+3) -2/(x+4)+7x/(x²+3).
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.