Nd all poles of the rational function and their multiplicities, write the partial fraction decomposition?

A/(x+4)+(Bx+C)/(x²+3) (Ax²+3A+Bx²+Cx+4Bx+4C)/(x²+3)(x+4) Ax²+Bx²=5x² A+B=5 A=5-B Cx+4Bx=28x C+4B=28 C=28-4B 3A+4C=-6 plug in A=5-B and C=28-4B 3(5-B)+4(28-4B)=-6 15-3B+112-16B=-6 -19B=-133 B=7 A=5-B A=-2 C=28-4B C=0 A/(x+4)+(Bx+C)/(x²+3) -2/(x+4)+7x/(x²+3).

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