The height is equal to the diameter, so r = h/2. .. V = 1/3? (h/2)^2 h .. V =?
/12 h^3 The rate of change of volume with respect to time is .. dV/dt =? /4 h^2 dh/dt so .. dh/dt = (4 dV/dt)/(? h^2) .. dh/dt = (4* 50 ft^3/min) / (? (16 ft)^2) = 25/(32?) ft/min Height is increasing at the rate of 25/(32?)? 0.249 ft/min.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.