Net Xml Deserialization?

Try this: public class Issue { XmlAttribute public string Type { get; set; } XmlAnyElement("Record") public List Record { get; set; } } I think that tells the serializer that multiple Record elements will go in the list.

Changing that to XmlAnyElement seemed to work – Chad Oct 5 '10 at 17:51 Ah nice, thanks. – Simon Steele Oct 5 '10 at 18:35.

Implement Record class which has ID, Name_First, Name_Last and Company fields.

I don't want a class, I want an XElement as the record could contain anything. – Chad Oct 5 '10 at 17:27.

Preferably not. – Chad Oct 5 '10 at 17:27.

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