Ok so I have this question on my homework and I cannot seem to figure it out. help?

Ok so I have this question on my homework and I cannot seem to figure it out. Help? A compound containing only C, H, and N yields the following data.(i) Complete combustion of 33.7 mg of the compound produced 32.3 mg of CO2 and 39.6 mg of H2O.(ii) A 64.2-mg sample of the compound was analyzed for nitrogen by the Dumas method, giving 35.1 mL of N2 at 740.

Torr and 25°C(iii) The effusion rate of the compound as a gas was measured and found to be 24.6 mL/min. The effusion rate of argon gas, under identical conditions, is 26.4 mL/min. What is the molecular formula of the compound?

Asked by Rayray1992 26 months ago Similar questions: question homework figure help Science > Chemistry.

Similar questions: question homework figure help.

Wikipedia:Help desk When I search for "CCAI", the Congressional Coalition on Adoption Institute article does not come up (even though the article mentioned it is referred to by the acronym). Also, when I search "Congressional Coalition", it comes up as "Congressional Coalition on Adoption", which was the old name of the article. How can I fix this?

—Preceding unsigned comment added by Scrumo (talk • contribs) 05:57, 24 October 2009 (UTC)If we do not have a page named CCAI that redirects the user to that page, then a user won't be redirected. I created a disambig page for it now as there are multiple meanings for the acronym. Second, the search is indexed every couple of days, which means that either new or recently changed article's won't have been updated yet.

Give it a couple of days and see if it updates. That virtually always solves the problem :) Excirial (Contact me,Contribs) 06:48, 24 October 2009 (UTC)editCecile O'Rahilly~audio fileSome time ago, I posted an audio file of this scholar reading the first 100 lines or so of the *Tain Bo Cuailgne*. Will it ever be available for use..., for anyone?

Access seems strangely blocked. -Raymond CormierRjmcormier (talk) 13:50, 24 October 2009 (UTC)Files are available for use as soon as they are uploaded, unless they are deleted. If you are referring to the file TBC-ORah3.

Ogg uploaded to Wikimedia Commons in November 2008 then 1 shows it was deleted a month later for missing license information. Many recordings are copyrighted and there has to be a license which allows the upload. See for example commons:Commons:Licensing.

PrimeHunter (talk) 14:13, 24 October 2009 (UTC)editDaniela CicarelliI removed a link to a paparazzi sex video and most of the article--it seemed pov and cruel to Cicarelli. Was I right to do this under BLP? Someone has reverted my edit.

ThanksRich (talk) 14:06, 24 October 2009 (UTC)BLP mostly deals with material that is poorly sourced (i.e. Libellous), and that doesn't seem to apply here. The material was well-sourced.As the reverting user implied, you should have at least started a discussion on the talk page before removing the material; perhaps some of it could have been saved.

Xenon54 / talk / 15:00, 24 October 2009 (UTC)ok, thanksRich (talk) 23:03, 24 October 2009 (UTC)I've thought about it a bit more, and I think that if what you say is correct wikipedia policy then it's pretty messed up. Linking the video is rather discourteous whether or not i'ts legal and well-sourced. Yes, she is a famous person, but "he" may not be, although that's hardly one of my main points.

Sources: http://en.wikipedia.org/wiki/Wikipedia:Help_desk .

With Graham's Law, you can find the effusion rates for two gases or the molecular mass of a gas. Graham's Law The ratio of the rates of effusion of two gases is equal to the square root of the inverse ratio of their molecular masses or densities. The effusion rate of a gas is inversely proportional to the square root of its molecular mass.

Mathematically, this can be represented as:Rate1 / Rate2 = square root of (Mass2 / Mass 1)Explanation and Discussion:Graham's Law shows the relationship between the molar or molecular mass of a gas and the rate at which it will effuse. Effusion is the process of gas molecules escaping through tiny holes in their container. Diffusion can also be considered with Graham's Law, such as perfuming diffusing through a room.

Let us first consider why gases effuse. Containers can have small holes or pores in them. Although these openings are microscopic, they are larger than the gas molecules.

Randomly, the gas molecules move around the inside of the container until they impact something. This can be another molecule or the side of the container. A gas can also, instead of hitting the side of the container, pass through one of those openings by chance.

This is effusion: a random movement of a as molecule through the container's wall. A common example of this is a balloon filled with helium: first it is buoyant and floats in the air, but in a few days it hangs toward the ground or floats a few inches above the ground (if at all). The Helium has escaped through the small holes in the balloon.

With Graham's Law, you can find the effusion rates for two gases or the molecular mass of a gas. This ratio of effusion rates follows the pattern that the gas with the lesser molecular mass has a greater rate of effusion. Calculations using Graham's LawLet's compare the rate off effusion of two common gases, Nitrogen and Oxygen.

N2, Nitrogen, has a molecular mass of 28.0 g. O2, Oxygen, has a molecular mass of 32.0 g. Therefore, to find the ratio, the equation would be:RateN2/RateO2 = square root of 32.0 g / 28.0 g.

This works out to:RateN2/RateO2 = 1.069 Sources: http://library.thinkquest.org/12596/graham.html .

Ok so I have this question on my homework and I cannot seem to figure it out. Help FIELD OF THE INVENTIONThe present invention relates to utilization of renewable resources and industrial wastes, such as pulp and paper sludge and products of their incineration, and in particular to recovery of minerals from these materials. BACKGROUND OF THE INVENTIONPulp and paper sludge (a byproduct of primary pulping operations, recycle streams or waste paper pulping and the like), as well as the products of its incineration, represent an environmental and disposal problem for manufacturers of pulp and paper.

Generally, pulp and paper sludge is unsuitable for paper making, although it generally includes the same components--lignin, cellulose, hemicellulose, calcium carbonate, clay, and other inorganic components--as those present in the paper pulp itself. Paper sludge has traditionally been disposed of by landfilling, composting, utilization by the cement industry, and by incineration. The latter option, in turn, creates another problem, namely, disposal of the resulting ash, which often constitutes up to 50% (and sometimes as much as 80% or higher) of the volume of the sludge itself.

Calcium carbonate, in the form of precipitated calcium carbonate (PCC) or ground calcium carbonate (GCC), typically constitutes 20% and up to 75% of dry sludge content. Calcium carbonate is a natural carbonate which is loaded, typically together with clay, into paper as a coating and filler to improve the mechanical characteristics as well as the appearance of paper. Despite their natural abundance, calcium salts are generally expensive products because of the difficulties and expenses of their purification from natural mineral deposits.

For instance, paper-quality PCC is typically produced from natural limestone via many stages including the calcination of limestone in an industrial kiln (into either a calcitic or a dolomitic lime), slaking, slurrying, carbonating, and a number of refining steps. Calcium-derived compounds undergo chemical changes when paper sludge is incinerated. These changes were outlined in recent articles (see Sohara, "Recycling Mineral Fillers from Deinking Sludges," Paper Recycling '96 Conf.1996) (hereafter "Sohara"); Pera et al.

, "Paper Mill Sludge: A Source of Valuable Cement Additives," Paper Recycling '96 Conf. (1996). The organic components of sludge are completely destroyed during incineration.

Thermal dehydration of clay results in calcined aluminosilicates, which form complex chemical compounds with decarboxylated calcium carbonate of general formula Can Ala Sib Oc, that is, calcium aluminosilicates. Silica, which enters the thermally treated sludge from the fluidizing medium (sand) during the incineration process and also as a product of kaolin thermal breakdown, reacts with calcium oxide (derived from thermal decarboxylation of calcium carbonate) forming calcium silicate CaSiO3. Other minerals present in sludges (as pigments, fillers, traces of flocculants, etc. ), such as those based on magnesium, potassium, titanium and others, make the composition of the mineral content even more complex.

The particular species formed depends mainly upon the relative amount (and nature) of clay in the mineral fraction of the sludge, the amount of calcium carbonate, and the conditions of the thermal treatment. Formation of calcium silicates in the course of incineration of lime-treated "green liquor" residues, containing calcium carbonate and silica, was described in Chattaraj et al. , Indian Pulp & Paper, June-July 1981, at 21-28.

Such an incineration leads to the formation of di- and tri-calcium silicates (presumably, larnite Ca2 SiO4 and gehlenite Ca2 Al2 SiO7 among them), which in turn form a fine gelatinous precipitate of calcium silicate dihydrate in the caustic liquor ("white liquor"). The authors reported that calcium silicates make calcination of calcium carbonate more difficult. Moreover, calcium silicate particles that are formed as a result of the calcination process are fused into irregularly shaped abrasive agglomerates unsuitable for paper filling and coating; see Johnston et al.

, Appita Journal, 49(6):397-402 (1996). Lacking in the prior art is a cost-effective method of producing pure, high-grade calcium and other mineral salts from papermaking sludge or ash derived therefrom. Sources: http://www.patentstorm.us/patents/5919424/description.html .

Quebec Newspaper Writes Editorial Against Homework Too much homeworkAs kids go back to school, we need to pay attention to a growing movement among parents and educators calling on homework to be severely reduced. We think they are right. Childhood is a time for growth and education is an important part of that.

But so is being a child. Enjoying your youth and family. School hours have expanded over the years to the point that many school days end at five instead of three.

Almost weekly tests in one subject or another are being the norm in many schools. Homework assigned, or studies expected, reach two to three hours a night. It is far too much.

Kids and families need to decompress at the end of a day. Kids need time to be kids and families need time to be families. It can’t just be school, rush home and grab a quick dinner, and back to the books.

Monastic existences do no one any good. We need to ask why this is happening. We all know about the explosion of information.

But we have to ask about what happened to the three Rs, reading, writing and arithmetic. We know more is now required. But two hours of homework a night for primary school kids who need their parents to help them is over the top.

We need to examine just how good the “pedagogie” is coming out of Quebec. We also have to look at whether things like not having enough English textbooks is one of the reasons for so much homework on the English side, although in all fairness the problem is just as acute on the French side. We need to look at the qualifications of teachers as well.

Just yesterday, a Montreal newspaper reported that there is such a drastic shortage of teachers that some schools are hiring teachers — and there are almost a hundred — who only have a high school or Cegep diploma. If lack of teachers and large class sizes are problems, then we have to ask the provincial government to make teaching a more attractive profession. Stressing kids and parents is not the answer.

Teachers are professionals. As professionals they are tasked with imparting knowledge to children during a given part of the day. They are also public servants.As such we have a legitimate right to ask why are they not completing their tasks in the appointed time and “offloading” their work onto families?

If Quebec is throwing too much information into the pedagogy, let’s cut it. If the use of homework and weekly exams is some kind of shock treatment by teachers to concentrate the minds and sphincters of students, let’s stop it. Sources: http://stophomework.com/quebec-newspaper-writes-editorial-against-homework/1413 .

Here are the steps... This is a fun type problem to work. Here are the steps.1. Calculate the percent C and H in the sample.(convert mg of CO2 to mg of C and mg of H2O to mg of H; divide each by the 35 mg sample size to get percentages.

)2. Calculate the percent N2 in the 65.2 mg sample.(use the PV=nRT formula to calculate the moles of N2 and then calculate the mg; g/28 = moles. )3.

Assume a 100 gram sample.(26.1% C becomes 21.6 g C) Calculate the moles of C, H, and N in the 100 g sample.4. Divide the moles by the smallest number to get a ratio of moles. (For example if the ratios of an imaginary compund were: 1 of A, 3.5 of B, and 1.5 of C then the empirical formula would be A2B7C3)3.

The rate of effusion of the unknown divided by the rate of effusion of Ar = the square root of (the MW of Ar divided by the MW of the unknown compound)26. 4/24.6 = sqrt(39.95/MW)1.1517 = 39.95 / Mol Wgt4. The molecular formula will be a multiple of the empirical formula (1X, 2X, etc)Now you can learn how to do this type of problem by carrying out each step.

Sources: http://answers.yahoo.com/question/index?qid=20071115205555AAHBBDX .

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I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.