Passing pointers with space allocated by malloc?

Yes calling free will free the memory. Its not the pointer that get freed but the memory that the pointer points to that is freed.

Thank you! I'm guessing the information on how much memory was allocated is stored elsewhere, so that when 'free' is called, it knows how much to free up? – Russbear Jun 1 at 18:01 Yes, that is correct.

– Richard Schneider Jun 1 at 20:34.

You must pass to free() the value obtained from malloc(). Int *x = malloc(42 * sizeof *x); int *p = &x0; free(p); /* ok, same as free x; x and p have the same value */ Edit: another example int *x = malloc(42 * sizeof *x); for (k = 0; k.

1 the value is the key here and what OP doesn't seem to understand. – R.. May 31 at 0:12.

Then the answer is "no" -- you must pass free() the exact pointer which you got back from malloc(). Trying to free() an internal pointer, or a pointer to memory which was not allocated by malloc(), memory corruption or a crash are likely to occur.

I think you misunderstood OP's question. – R.. May 31 at 0:12.

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