Photons per second emitted by a laser?

Ooooh -- too little information for an exact answer, because different types of bulbs (incandescent, fluorescent or CF=compact fluorescent, LED=light-emitting diode) have very different efficiencies, which is to say, the amount of light produced for each Watt of power consumed (light bulb power ratings are in power consumed, not light output power). I'm guessing this question came from the time when all common light bulbs were tungsten-filament incandescent, because 100 W is a common value for one of those, and not for the others (CF's are more than 4 x as efficient, e.g., and a 23-W CF claims the same light output as a 100-W incandescent!). In that case, the wiki article in the Source area below, gives the light-generating efficiency as 2.6%.

So while consuming 100 W, it emits P = 2.6 W = 2.6 J/s of light. Now the problem reduces to dividing P by the photon energy, the result of which will be photons per second. (If you have different information on the light output power, you can use that in place of the 2.6 W.) Photon energy, E = hƒ, where: h = Planck's constant = 6.626•10^-34 J•s ƒ = frequency = 5•10^14 Hz = 5•10^14 /s, in this case a Hz is a cycle per second so E = 3.313•10^-19 J P/E = 2.6 W / 3.313•10^-19 J = 7.85•10^18 /s Timsel: Mark P's answer would be right if a 100-W bulb emitted 100 W of light, but it doesn't come anywhere near that; it's smaller by a factor of almost 40.

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