Problema geometria?!?

Il triangolo ACK è rettangolo perchè inscritto n una semicirconferenza. Di questo conosciamo: l'ipotenusa AK, che è il diametro della circonferenza (30 cm) il cateto KC (18 cm) Con Pitagora troviamo AC: AC = rad.q. (AK^2 - KC^2) = rad.q.

(30^2 - 18^2) = 24 cm Con Euclide troviamo AH: AH = AC^2/AK = 576/30 = 19,2 cm Con Pitagora: HC = rad.q. (24^2 - 19,2^2) = 14,4 cm, quindi BC = 2 * 14,4 = 28,8 cm Area triangolo ABC = 28,8 * 19,2/2 = 276,48 cm^2 Area cerchio = 15 * 15 * p greco = 706,5 cm^2 Area aree colorate = Area cerchio - area triangolo = 706,5 - 276,48 = 430,02 cm^2.

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