Python: Assign multiple values at once: pass all argv arguments to a function?

You're calling createP before you define it. You're also passing the wrong number of arguments to it; you need to expand the array.

You're calling createP before you define it. You're also passing the wrong number of arguments to it; you need to expand the array: def createP( a, b, c): print a + be + c if __name__ == "__main__": import sys createP(*sys. Argv1:).

Try switching the order between the definition and the if.

Yes. The function needs to be defined first before I can call it.. Thanks! – Gurk Aug 26 '11 at 13:07.

You must inverse the order, as already said. And to display variable lengths of argv, you should write: def createP(*x): print '\n'. Join(x) # or ' '.

Join(x) if you prefer if __name__ == "__main__": import sys createP(*sys. Argv1:) I suppose that all elements of sys. Argv are strings.Am I right?

Update Well, my answer is a bit stupid; why the following code (without * for passing arguments and for definition of parameters) wouldn't be convenient? : def createP(x): print '\n'. Join(x) # or ' '.

Join(x) if you prefer if __name__ == "__main__": import sys createP(sys. Argv1:).

Two things: you go into the body of if __name__ == "__main__": before createP is defined. Your function definition enforces 3 arguments but you pass in only 1 (a list object). So: def createP(a, b, c): print a + be + c if __name__ == "__main__": import sys createP(*sys.

Argv1:).

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