Dibujando la situación, se forma un gran triángulo: su base mide 250 m. Hay que calcular su altura, que corta a la base en un punto: x, (250-x) Por la fórmula de la tangente trigonométrica: tan(30º) = altura / x --> despejando altura = x. Tan(30º) tan(41º) = altura / (250-x) --> altura = (250-x).
Tan(41º) Igualando ambas alturas: x. Tan(30º) = (250-x). Tan(41º) x.
Tan(30º) = (250. Tan(41º) - x. Tan(41º) 0.577x = (250por0.87) - 0.87x (0.577+0.87).
X = 217.32 1.447x = 217.32 x = 217.32 / 1.447 x = 150 m. En la base Teníamos: altura = x. Tan(30º) altura = 150.
Tan(30º) altura = 86.71 m de altura.
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