Qualcuno puo aiutarmi con un problema di trigonometria?

L'ampiezza di ciascun angolo alla base. Cos(?) = (?5)/3 sen(?) =?(1 - cos²(?)) =?(1 - 5/9) =?(4/9) = 2/3 sen(2?) = 2sen(?)cos(?) = (4?5)/9 cos(2?) = cos²(?) - sen²(?) = 5/9 - 4/9 = 1/9? = 180° - 2?

Sen(?) = sen(180° - 2?) = sen(2?) = (4?5)/9 cos(?) = cos(180° - 2?) = - cos(2?) = - 1/9 (il triangolo è ottusangolo) tan(?) = sen(?)/cos(?) = ((4?5)/9)(-9) = - 4?5 cot(?) = 1/tan(?) = - 1/(4?5) = (-?5)/20.

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