You shouldn't have $gquery in quotes. You should use $result = mysql_query($gquery) or die(mysql_error()).
Yep, you're trying to execute '$gquery' as a String, but not the value of the variable. – Fiarr Aug 21 '09 at 20:19 I tried both ways but still the same problem – Javier Aug 21 '09 at 20:23 Does your php file only have this line? Or is there more code that could be causing the problem?
– Rob Aug 21 '09 at 20:27 Is in that exact line that it stops until it gives timeout (i have some echo for debug) There is more code but I guess the problem has to do with the query, because when I change it, everything works fine. – Javier Aug 21 '09 at 21:05 It may be due to the nested query.. – Javier Aug 21 '09 at 21:09.
SOLVED: timeout issue. It was necessary to extend the timeout period. Sorry.
I run this as 1 query from phpmyadmin. It run's Ok. But I don't see this in routines table in information_schema.
Pls help me, what happens?
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