¿quien me puede ayudar, socorro, necesito ayuda?

Hola David: Practica con factores de conversión y transformación. A)) Frente a 0,1 N de ácido, el factor de transformación es: (27,8 / 50) establecido con los volúmenes comparativos. Luego: Normalidad NaOH=0,1N (27,8 / 50)= 0,0556 N de NaOH.

Rpta. B))(0,0556 mol-g NaOH / L)(40g NaOH / 1 mol-g NaOH)(1000 mg NaOH / 1 g NaOH)(1 L / 1000 cm3)= 2,224 mg NaOH / cm3. Rpta.

Que tengas un buen día. Saludos. Soy Químico.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.