Regular expression to match binary words?

Three consecutive zero chars: b01*0{3}01*\b Note It is not entirely clear whether this is what OP wants Edit Apparently it was :).

Three consecutive zero chars: \b01*0{3}01*\b Note It is not entirely clear whether this is what OP wants. Edit Apparently it was :).

B(1*0){3} will also match if the three zeros are not consecutive. This only matches as much as required (i.e. Up until the third zero).

If you want it to match the entire number, use \b(1*0){3}01*\b.

1 Elegant and nice thought to only match "as much as required". – jensgram May 12 '10 at 11:04.

– Amarghosh May 12 '10 at 12:26 right, the statement should've been written as"a number of zeros that can be divided by 3" :) – Noona May 12 '10 at 20:26.

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