Ruby regular expression using gsub?

You can simply remove 0s in parts that ends with a slash Works for me require "date" class Date def m_d_y strftime('%m/%d/%Y'). Gsub(/0(\d)\//, "\\1/") end end puts Date. Civil(1980, 1, 1).

M_d_y puts Date. Civil(1980, 10, 1). M_d_y puts Date.

Civil(1980, 1, 10). M_d_y puts Date. Civil(1908, 1, 1).

M_d_y puts Date. Civil(1908, 10, 1). M_d_y puts Date.

Civil(1908, 1, 10). M_d_y outputs 1/1/1980 10/1/1980 1/10/1980 1/1/1908 10/1/1908 1/10/1908.

You can simply remove 0s in parts that ends with a slash. Works for me require "date" class Date def m_d_y strftime('%m/%d/%Y'). Gsub(/0(\d)\//, "\\1/") end end puts Date.

Civil(1980, 1, 1). M_d_y puts Date. Civil(1980, 10, 1).

M_d_y puts Date. Civil(1980, 1, 10). M_d_y puts Date.

Civil(1908, 1, 1). M_d_y puts Date. Civil(1908, 10, 1).

M_d_y puts Date. Civil(1908, 1, 10). M_d_y outputs 1/1/1980 10/1/1980 1/10/1980 1/1/1908 10/1/1908 1/10/1908.

This actually works, lol, thanks Vincent – Alex Baranosky Feb 6 '10 at 8:59 A minor variant also works nicely: strftime('%m/%d/%Y'). Gsub(/0(\d{1})\//, "\\1/") – Alex Baranosky Feb 6 '10 at 9:23 Yes, Alex. The default counter is {1} so it is not necessary, except for clarity, also "*" is equivalent to {0,} and "+" equivalent to {1,} – Vincent Robert Feb 6 '10 at 9:50 Or using positive look-ahead, you can do strftime('%m/%d/%Y').

Gsub(/0(\d)(?=\/)/, '\1'). – kejadlen Feb 6 '10 at 15:40.

02/02/1980". Gsub(/\b0/, '') #=> "2/2/1980" \b is a zero-width marker for a word boundary, therefore \b0 cannot have a digit before the zero.

Require "date" class Date def m_d_y mon, mday, year. Join("/") end end.

Nice, thanks... – Alex Baranosky Feb 6 '10 at 19:02.

AFAIK (and according regular-expressions.Info/lookaround. Html) Ruby does not support look-behinds and replacement-interpolation is done through '\1' (including quotes! ) instead of $1.

– Bart Kiers Feb 6 '10 at 18:55 I am not sure with other ruby, but ruby 1.9 support that. – YOU Feb 7 '10 at 3:10.

The problem is that it won't match valid dates so your replacement will mangle valid strings. To fix: Regex: (^|(?

– Alex Baranosky Feb 6 '10 at 8:52 Ruby does not support look-behinds. See: regular-expressions.Info/lookaround. Html – Bart Kiers Feb 6 '10 at 18:37.

You say that Ruby is throwing a syntax error, so your problem lies before you have even reached the regexp. Probably because you aren't calling strftime on anything. Try: def m_d_y t = Time.

Now t. Strftime('%m/%d/%Y'). Gsub(/0?(\d{1})\/0?(\d{1})\//, $1 + "/" + $2 + "/" ) end Then replace Time.

Now with a real time, then debug your regexp.

I was calling strftime from within the Date class :) – Alex Baranosky Feb 6 '10 at 9:22 Well then. Not sure where the downvote came from, but whatever. – Ben Feb 6 '10 at 10:07.

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