En todo octagono regular se cuumple que: P=lado x 8 A=2r^2Raiz de 2 ó (perimetro x apotema)/2 El octágono está formado por 8 triángulos isosceles o sea 16 triángulos rectángulos. Separamos uno de los 16, que tendrá las medidas siguientes: A=22.5° B=67.5° C=90° a=? (la mitad del lado del octágono) b=?
(apotema del octágono) c=10dm (radio de la circunferencia) a=c sen A a=10(0.3827) a=3.827dm < -------- (lado del octágono=7.654dm) P=7.654 x 8 = 61.232dm (Perimetro) b=Raiz de c^2-a^2 b=Raiz de 100-14.646 b=Raiz de 85.354 b=9.239dm (apotema) A=(61.232 x 9.239)/2 A=282.56 dm^2 (Area).
Lo siento, es es verdad, disculpen las molestias.
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