Solving logarithm equation?

Has to equal , since loge(e)= 1 xln(e)=x, x=ln13 x=2.565 2)log3(x+1)^2=6, bring the 2 down to the front, 2 log3(x+1)=6, log3(x+1)=3, 3^3=x+1 x+1=27, x=26 3) Recall log(a)+log(b)=log(ab), log6(x)+log6(2)=log6(2x), log6(2x)?2 6^2=2x 2x=36 x=18 x?18 4) Recall that log(a)-log(b)= log(a/b) log(x-5)-log(3)=log(x-5/3), log(x-5/3)=1, rewrite in exponential 10^1=(x-5)/3 (remember log without base assume base is 10) 10=(x-5)/3, multiply both sides by 3 30=x-5, x=35,check plug in 35 log(35-5)=log(30), log30-log3=log(30/3), log(10)=1 which is true I hope this is helpful!

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.