The square root of twice a certain number is subtracted from the number and the result is 4.Find the number?

Suppose the number is x Then x - sqrt(2x) = 4 x - 4 = sqrt(2x) Squaring both sides: x 2 8x + 16 = 2x So that x 2 10x + 16 = 0 Factorising: (x - 2)(x - 8) = 0 So x = 2 or x = 8 Remember that sqrt(4) can also be -2.

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