TSQL: Cannot perform an aggregate function AVG on COUNT(*) to find busiest hours of day?

The number of days is known and it is equal to DATEDIFF(day,CONVERT(DATETIME,'2009.01.01',120),CONVERT(DATETIME,'2009.09.01',120)). You have to calculate sum and divide it by number of days in selected range.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.

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