Verify the trig identity: (1-sin?)/(1+sin?) = (sec?-tan?)²?

Tan?)² I used the product of sum and difference shortcut to get a difference of squares in the first line's denominator. The last line just applies the definition of the tan and sec functions...or "quotient identities" sec? = 1/cos?

, tan? = sin? / cos?

1) Multiplying both nr. And dr. by {1 - sin(?)}, Left side = {1 - sin(?)}²/(1 - sin²? ) since (a+b)(a-b) = a² - b² = {1 - sin(?)}²/(cos²?) = {1/cos(?) - sin(?)/cos(?)}² = {sec(?) - tan(?)}² Proved.

Two things are infinite : the universe and human stupidity; Im not sure about the universe.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.