So, algebraically: X + (X+2) + (X+4) + (X+6) = 56 (Just identifying the first number and the consecutive odd digits which are always +2 more than the last one) X + X + 2 + X + 4 + X + 6 = 56 4X + 12 = 56 4X = 44 X = 11 Therefore, the four numbers are 11, 13, 15, 17.
What are four consecutive odd integers that equal 56 The integers would be 11,13,15 and 17. What is an interger -----quote---- An integer is what is more commonly known as a whole number. It may be positive, negative, or the number zero, but it must be whole.In some cases the definition of whole number will exclude the number zero, or even the set of negative numbers, but this is not as common as the more inclusive use of the term.
Integers are the numbers people are most familiar with, and they serve a crucial role in virtually all mathematics. ----quote---- Information quoted from wisegeek.com/what-is-an-integer.htm 11+13+15+17=52.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.