What is the best approach to have an ajax form and table in the same page without the need to refresh?

Take a look at this explanation of jQuery's ajaxForm and ajaxSubmit: justwebdevelopment.com/blog/ajaxform-and....

To execute code after the $.load() method has completed you need to place it in the callback of the call to load(). For example: $("#myElement"). Load( '/location/of-target.

Html', function(data) { // put code here to execute after the load has completed. // for example to append a specific div. $(data).

Find("#myDiv"). AppendTo("#containerDiv"); } ); Further reading here.

But I cant execute the same function in the callback and document. Ready otherwise, the code code bind to a click will be executed twice on click, right? – malkawi Dec 10 at 17:04.

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