(0.3784 g KHP) / (204.22 g KHP/mol) x (1 mol NaOH / 1 mol KHP) / (0.02360 L) = 0.07851 mol/L NaOH.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.