What is the most efficient way to reverse an array in Javascript?

Native methods are always faster So use Array. Reverse where possible. Otherwise an implementation that runs in O(1) would be best ;) Otherwise just use something like this var reverse = function(arr) { var result = , ii = arr.

Length; for (var I = ii - 1;i! == 0;i--) { result. Push(arri); } return result; } Benchmark!

Interesting the loop is faster if you use all three stages of the for construct instead of only one for(var I = ii - 1; I! == 0;i--) is faster then var I = ii - 1;for(;i--! == 0;).

Native methods are always faster. So use Array. Reverse where possible.

Otherwise an implementation that runs in O(1) would be best ;) Otherwise just use something like this var reverse = function(arr) { var result = , ii = arr. Length; for (var I = ii - 1;i! == 0;i--) { result.

Push(arri); } return result; } Benchmark! Interesting the loop is faster if you use all three stages of the for construct instead of only one. For(var I = ii - 1; I!

== 0;i--) is faster then var I = ii - 1;for(;i--! == 0;).

I believe forward loops are faster than reverse loops. You should try testing it out using this implementation as well as, for(int I =0, I Com/js-array-reverse-vs-while-loop – Matt McDonald Mar 11 at 19:20 @Matt McDonald Interesting, we just did a project in college proving otherwise lol. Although we tested all sorts of functionality like bubble-sort, heap-sort, quick-sort.

The timing on stuff like this has a lot to do with how the array is already layed out.(Is it already sorted, is it already random? ) Different types of sorts / reverse sorts often depend on the initial state of the array. It is hard to PROVE which is fastest as their are many many different scenarios.

– Chris Buckler Mar 16 at 21:46.

Here's a java example leepoint.net/notes-java/data/arrays/arra... showing how to reverse an array. Very easy to convert to javascript. I would suggest using something that simply captures the time before the function is called, and after the function is called.

Which ever takes the least time / clock cycles will be the fastest.

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