Why should the member function declarations of a class template be all well-formed?

When implicitly instantiating a class template specialization, the compiler has to inspect the complete declarator of that member because it needs to know basic information about the declaration. Such can contribute to the size of the class template specialization.

SFINAE is used only when creating a candidate set for a function overload resolution. In your first example, you are calling the overloaded f() function, and the first one is excluded thanks to SFINAE.

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