You are asked to go into the lab and prepare an acetic acid-sodium acetate buffer solution with a pH of 4.64 ±?

EDIT: You are right to be using the H-H equation. Ka = H+AcO/AcOH Ka/H+ = AcO/AcOH 1.7378x10^-5/1.5849x10^-5 = AcO/AcOH 1.096 = AcO/AcOH You got this far. Now according to your question you need the buffer to be 0.05M in NaOAc and you want to make 0.49 L total.

1.096 = 0.050/0.0456 Now a concentration of 0.05M means 0.05 mol in a litre. You say you need this in 0.49 litres. Therefore using ratios 0.05/1000 = x/490.

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