A 2.9 m length of straight wire carries a current of 30 A in a uniform magnetic field of 65 mT whose direction?

I suggest you use the Lorentz force law to compute the force: F = L * I X B Here L is the length of the wire, I is the current through the wire, and B is the magnetic field. The operator "X" denotes cross product. | I X B | = | I | | B | sin?

So the magnitude of the force per unit length F = L * | I X B | / L = | I | | B | sin? We have 0.25 A and 0.0255 T. And sin (30) = 1/2.

So F = 0.25 * 0.0255 * 1/2 = 0.0032 N /m = 3.2e-3 N/m.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.

Related Questions


Thank You!
send