We need to look at the amount of acetylene present in mols. Acetylene is C2H2. We are forming acetylene from 75.8 grams of carbon or 6.32 mol of C.
We are told that in acetylene there is 24.02 g of Carbon or 2 mol of C and 2 mol of H. From above, we have 6.32 mol of C and x amount of H. So, we need to find out how many more mol of H are needed, which is simply a ratio of 1:1 so we will require 6.32 mol of H too.
So that is just going to be 6.32 mol *1.01 g/mol = 6.38 g of H and 75.8 g of C.
X / 2.02 = 75.8 / 24.02 x = 2.02 * (75.8 / 24.02) x = 6.37g (to 3sf).
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