Elemental analysis of the compound which contains only carbon, hydrogen and oxygen gave the following results;?

Predicting chemical formulas.... You are essentially finding the empirical formula which comes from a whole-number ratio of moles. Compound I : 22.48g Pb and 27.52g I 22.48g Pb x (1 mol Pb / 207.2g Pb) = 0.108 mol Pb 27.52g I x (1 mol I / 126.9g I) = 0.217 mol I Pb: .... 0.108 mol / 0.108 = 1 mol Pb I: ........ 0.217 mol / 0.108 = 2 mol I PbI2 is the chemical formula Compound II : 5.80 g Pb 14.20 g I 5.80g Pb x (1 mol Pb / 207.2g Pb) = 0.0280 mol Pb 14.20g I x (1 mol I / 126.9g I) = 0.112 mol I Pb: .... 0.0280 mol / 0.0280 = 1 mol Pb I: ........ 0.112 mol / 0.0280 = 4 mol I PbI4 is the chemical formula The only catch is that whoever wrote the question didn't do their homework. While PbI2 exists, PbI4 does not.

In combination with iodine, lead will be reduced to Pb(II) while iodine is oxidized to I2. There are only a few compounds found in which lead is in the +4 oxidation state and PbI4 is not one of them. The bottom line is that there can be NO analysis which indicates that the formula is PbI4.

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