C6H12O6 + 6 O2 Then, you need to convert the number of grams of water into moles. The molar mass of water is 1+1+16=18 g/mol. Therefore, there are 3.3/18=.18 mol H2O.
Using mole ratios, there is one mole of H2O consumed per mole of O2 produced, so there will also be .18 mol O2 produced. O2 has a molar mass of 16+16=32g/mol, so 32(g/mol)*.18(mol)= 5.8 grams of O2 produced.
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