Balance C8H18 plus O2---CO2 plus H2O?

The way to do this is to use variables for the amount of each type of atom: a C8H18 + be O2 = c CO2 + d H2O You want to solve for a, b, c, and d Now, write an equation for each type of atom. In this case: For C: 8a = c For H: 18a = 2d For O: 2b = 2c + d I am leaving the fun part for you - to solve the simultaneous equations. Note: You have 4 variables, but only 3 equations.By solving, you will have relationships between the amounts, but no absolute amounts.

This is logical, for you can (for example) double each quantity, and the equation will still be valid. Adjust the final result so that you get integers. For example, if you get 1/2 of one type of molecule, and 1/3 of another, multiply by the common denominator (6 in this example).

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