Calculating change in finite denominations?

You should be able to reduce the complexity significantly by using the modulo operator.

Int num_100 = amount / 100; amount %= 100; int num_50 = amount / 50; amount %= 50; int num_20 = amount / 20; amount %= 20; int num_10 = amount / 10; amount %= 10; int num_5 = amount / 5; amount %= 5; int num_1 = amount.

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