Finite Math....Algebra Question?

A statistical study shows that the fraction of television sets of a certain brand that are still in service after x years is given by,f(x) = e^(-0.15x)a. What fraction of the sets are still in service after 5 years?b. After how many years will the fraction still in service be 1/10?

Asked by unearthlyjoy 43 months ago Similar questions: Finite Math Algebra Question Science > Math.

Similar questions: Finite Math Algebra Question.

I can help you, but I won't solve it for you! A. What fraction of the sets are still in service after 5 years?

The formula says that the fraction of sets in service after x years is e^(-0.15x) so: The fraction of sets in service after 1 year is when you substitute x by 1, i.e. E^(-0.15) The fraction of sets in service after 2 year is when you substitute x by 2, i.e. E^(-0.15*2)=e^(-.3) The fraction of sets in service after 3 year is when you substitute x by 3, i.e.

E^(-0.15*3)=e^(-.45) So, what is the fraction of the sets that are still is service in 5 years? B. After how many years will the fraction still in service be 1/10?

So, we want this fraction to be at least 1/10. Therefore we want f(x) to be at least 1/10. Which means: e^(-.15x) >= 1/10 You need to solve this inequality.To solve this inequality you need to take Ln from both sides and then solve that for x.

When you take Ln from both sides you get: -.15 x >= Ln (1/10). Solve that for x and you are done! Hope this helps you.

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2 I think that adding that topic makes it seem like I want it done for me... there is a difference between wanting it done for me and wanting help in understanding how to go about doing it. I am not a student but an adult who is studying on her own and very much would like to understand how it is done. You are misinforming everyone.. but have a nice nonjudgmental day anyhow..

I think that adding that topic makes it seem like I want it done for me... there is a difference between wanting it done for me and wanting help in understanding how to go about doing it. I am not a student but an adult who is studying on her own and very much would like to understand how it is done. You are misinforming everyone.. but have a nice nonjudgmental day anyhow..

Paradise. T replied to post #2: 3 Cool. I hope my answer helped you.

4 Thanks bonusquestion for your help and not a complete answer :) .

Thanks bonusquestion for your help and not a complete answer :).

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