CPP templated member function specialization?

It's a way to tell the compiler " the thing after -> is a templated call.

This syntax is looking weird. But is works! – Manuel Jul 26 '10 at 9:37 Yeah totally unusual.

But that's what it takes when using advanced templated c++ :-) – Scharron Jul 26 '10 at 9:45 1 @Manual: The problem is that A->BBB. If it is an object, then A->B– sbi Jul 26 '10 at 10:31.

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