Display “root” node in TreeView?

If you want a root you need to specify an ItemsSource with only one item in it, the root node, it has to be an IEnumerable the node itself cannot be the source.

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This is my code: Node node0 = new Node("Root"); Node node1 = new Node("Node1-1"); Node node12 = new Node("Node1-2"); Node node21 = new Node("Node2-1"); Node node22 = new Node("Node2-2"); Node node31 = new Node("Node3-1"); Node node9 = new Node("Node9"); node12.Children. Add(node21); node12.Children. Add(node22); node22.Children.

Add(node31); node1.Children. Add(node9); node0.Children. Add(node1); node0.Children.

Add(node12); treeView1. DataContext = node0; public class Node { List children; public List Children { get { return children; } set { children = value; } } string data; public string Data { get { return data; } set { data = value; } } public Node() { children = new List(); } public Node(string data) : this() { this. Data = data; } } c# wpf xaml treeview link|improve this question edited Jun 10 '11 at 15:08 asked Jun 10 '11 at 14:15anderi766 55% accept rate.

If you want a root you need to specify an ItemsSource with only one item in it, the root node, it has to be an IEnumerable, the node itself cannot be the source.

– anderi Jun 10 '11 at 15:11 Something like: treeView. ItemsSource = new List() { rootNode }; – H.B. Jun 10 '11 at 15:12.

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