Evaluate the line integral, where C is the given curve.?

Parameterize C by r(t) = for t in 0, 1. Then, r'(t) = . Ds = ||r'(t)|| dt =?29 dt.

Parameterize C by r(t) = for t in 0, 1. R'(t) = . Ds = ||r'(t)|| dt =?29 dt.?c xe^(yz) ds?(t = 0 to 1) 4te^(3t * 2t) *?29 dt 4?29?(t = 0 to 1) te^(6t^2) dt 4?29 * (1/12)e^(6t^2) {for t = 0 to 1}?29 (e^6 - 1)/3.

1 thus int over t in 0,1 of { 4 t e^(6t²) dt }...............{ e^ 6 / 3 }.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.