No. The first CD must contain song 1, song 2, .... song k. Then the second CD must contain song k+1, song k+2, .... and so on.
So all you are doing is deciding when to end the current CD and start the next. The solution to this problem is not complex and neither is the proof. However, this is a good problem to be sure that you understand how to prove that a greedy algorithm is correct.
If you feel that your solution is obviously correct and cannot prove it then you don't understand the mechanism provided in class to prove correctness and should come to our office hours and go over it with us. More.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.