Given a channel with an intended capacity of 20mbps the bandwidth of the channel is 3 mhz what snr in db is required in order to achieve this capacity?
C = Blog2(1+SNR) 20 = 3*log2(1+SNR) log2(1+SNR) =20/3 SNR = 100.6 SNRdb=10*log(SNR)=20 db.
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