70% remains) ... t = elapsed time ... half life = ... well.. . Half live So... 0.70 x Ao = Ao x (1/2) ^ (24hrs / half life) then.. log(0.70) = (24hrs / half life) x log(1/2) finally... half life = 24 hrs x log(1/2) / log(0.70) = 46.6 hours.
Radioactive decay is first order. Here's how I'd solve it: (1/2)^n = 0.7 n log 0.5 = log 0.7 n = 0.5146 (that's how many half-lives have elapsed) 24 hrs / 0.5146 = 46.64 hrs.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.