Help with evaluating a Triple Integral (Calculus III)?

X^2 dV?(x = -3 to 3)?(y = -?(9-x^2) to?(9-x^2))?(z = 0 to 11-x-2y) x^2 dz dy dx?(x = -3 to 3)?(y = -?(9-x^2) to?(9-x^2)) x^2 (11 - x - 2y) dy dx. Now, convert to polar coordinates:?(r = 0 to 3)?(? = 0 to 2?) (r cos?)^2 (11 - r cos? - 2r sin?) * (r d?

Dr)?(r = 0 to 3)?(? = 0 to 2?) r^3 (11 cos^2(?) - r cos^3(?) - 2r cos^2(?) sin?) d? Dr?(r = 0 to 3)?(? = 0 to 2?) r^3 (11 cos^2(?) - 0 - 0) d? Dr, due to symmetry?(r = 0 to 3)?(? = 0 to 2?) 11r^3 * (1/2)(1 + cos(2?)) d?

Dr?(r = 0 to 3) 11r^3 * (1/2)(? + sin(2?)/2) {for? = 0 to 2? } dr?(r = 0 to 3) 11?

R^3 dr (11? /4) r^4 {for r = 0 to 3} 891? /4.

I hope this helps!

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.