Calculus III problem help!~?

. F(x,y) = y^3 + 6xy^2 + 94x^2? 8x fx = 6y^2 + 188x?

8 fy = 3y^2 + 12xy Setting fy = 0, we get: 3y^2 + 12xy = 0 3y (y+4x) = 0 y = 0 or y =?4x For both cases, set fx = 0 y = 0 6y^2 + 188x? 8 = 0 0 + 188x? 8 = 0 x = 2/47 Critical point: (2/47, 0) y =?4x 6y^2 + 188x?

8 = 0 6(16x^2) + 188x? 8 = 0 24x^2 + 47x? 2 = 0 24x^2 + 48x?

X? 2 = 0.

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