How do I solve the following sin equation?

Use logarithm properties to take care of the x exponent xlog(sinx) = 1 now take the exponential of either side e^xlog(sinx) = e^1 reducing: xsinx = e take inverse sinx of both sides, but factor out the x first x(sin^-1(sinx)) = sin^-1(e) simplify: x=sin^-1(e).

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