I recommend going to wolframalpha. Com type it in just like that. It just gives you answers put its helpful.
E^(5*-2) - 2 0 Since f(x) is continuous in the interval -2,2 and f(-2) 0, then there must be some point -2.
Set f(x) = e^(5x) + x. First, we see that f(x) is continuous. We need to find a value x1 so that f(x1) 0.
I'll leave that to you. Thus, by IVT, because f(x1).
When x is a large negative number the exponential is small and the expression on the left is dominated by the x term, hence the expression will also be a large negative number. Likewise, when x is a large positive number both the exponential and the x term are large positive, so the expression takes on a large positive value. Lastly, the expression is the sum of two continuous functions and thus itself is continuous.So what we have is a continuous function that is negative somewhere and positive somewhere else, hence it must pass through zero so there must be a solution to the original equation.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.