Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.?

As it is fundamental you should learn it. If F(x) =?0 to x f(t) dt then d/dx (F(x)) = f(x) suppose f(x) =?0 to x (1+v^5)^9 dv df/dx = (1+x^5)^9 y = f(cos x) - f(sin x) dy/dx = df/d(cos x) d/dx(cos x) - df/d(sin x) d/dx(sin x) dy/dx = (1+cos^5 x)^9(-sin x) - (1+sin^5 x)^9 (cos x).

Sqrtx^2+1) dx --------------------------------------... Let g(t) = sqrt(x^2+1) f(R)= R g'(R) = g(f(R) f'(R) = - sqrt(R^2+1) (1) g'(R) = - sqrt(R^2+1).

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