How to write a length function using foldr in Haskell?

Thanks, it works! :) God Bless you – user962775 Oct 11 at 17:30.

The first argument of foldr must be a function of type a -> be -> be where a is the type of your list elements and be is the type of the accumulator. But here, you don't care about the value of the items of the list : the function just has to add 1 to the accumulator for each element. So the answer would be : length' = foldr (\_ -> (+1)) 0.

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