Math Help. Solving Quadratic Equations by Factoring.?

2x(x^2 + 7x - 5) = 0 So x = 0 is one factor. To find the other two factors consider the term: x^2 + 7x - 5 = 0 no obvious solutions factors so let's complete the square: x^2 + 7x + 49/4 - 49/4 - 5 = 0 (x + 7/2)^2 -69/4 =0 (x+7/2)^2 = 69/4 (x+7/2) = +/- sqrt(69/4) x = sqrt(69/4) - 7/2 or x = -7/2 - sqrt(69/4) so your solution set is {-7/2 - sqrt(69/4), sqrt(69/4)-7/2, 0}.

2x³ + 14x² - 10x = 0 2x(x² + 7x – 5) = 0 So, 2x = 0 or x² + 7x – 5 = 0 x = 0 but x² + 7x – 5 = 0 does not factor nicely, so you will have to use the quadratic formula. I hope you know what that means Quadratic formula explained: http://www.purplemath.com/modules/quadfo...

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