With char *p2 you allocate 2 char on the stack. When accessing p2 you have a buffer overflow and might access any other fings belonging to the stack frame of the current method (some compilers check this in debug mode).
P is declared to have two elements, so p2 does not exist - hence the segfault. Since p is a local array (of pointers), sizeof(p) gives the size of the element type (and the element type is char *, whose size is 4) multiplied by the number of elements (2). Pp, on the other hand, is a pointer (to a pointer), not an array, so sizeof(p) is simply the size of a char **, which is the same as the size of any other pointer on a 32-bit machine, namely 4.
That the assignment to pp2 seems to succeed is pure chance - you're writing outside the allocated memory (which only contains space for two char * elements).
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