Python and ctypes: how to correctly pass “pointer-to-pointer” into DLL?

Post actual code. The C/C++ code doesn't compile as either C or C++. The Python code has syntax errors ( ending function call Foo).

The code below works. The main issue after fixing syntax and compiler errors was declaring the function stdcall so windll could be used in the Python code. The other option is to use cdecl (normally the default) and use cdll instead of windll in the Python code mydll.

C (cl /W4 /LD mydll. C) include __declspec(dllexport) void __stdcall Foo(unsigned char** ppMem, int* pSize) { char i; *pSize = 4; *ppMem = malloc(*pSize); for(i = 0; I Foo Foo. Argtypes = POINTER(POINTER(c_ubyte)),POINTER(c_int) mem = POINTER(c_ubyte)() size = c_int(0) Foo(byref(mem),byref(size)) print size.

Value,mem0,mem1,mem2,mem3 Output 4 0 1 2 3.

Post actual code. The C/C++ code doesn't compile as either C or C++. The Python code has syntax errors ( ending function call Foo).

The code below works. The main issue after fixing syntax and compiler errors was declaring the function __stdcall so windll could be used in the Python code. The other option is to use __cdecl (normally the default) and use cdll instead of windll in the Python code.Mydll.

C (cl /W4 /LD mydll. C) #include __declspec(dllexport) void __stdcall Foo(unsigned char** ppMem, int* pSize) { char i; *pSize = 4; *ppMem = malloc(*pSize); for(i = 0; I Foo Foo. Argtypes = POINTER(POINTER(c_ubyte)),POINTER(c_int) mem = POINTER(c_ubyte)() size = c_int(0) Foo(byref(mem),byref(size)) print size.

Value,mem0,mem1,mem2,mem3 Output 4 0 1 2 3.

Thanks! Isolated code really works. Shame that I do not isolate it myself and tinkered with large codebase.It was a bug in my python code and 221 was freed memoty :) – Eye of Hell Nov 19 '10 at 8:17.

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