That unmarked IC chip is probably an Comparator Op amp. And when its load is shorted or too small it will only let 25mA of current flow out of it and thats probably where your losing most of your power.
The MJE200 is just a NPN transistor. If it uses many LEDs, then you may be able to rewire it to operate on a lower voltage. Do you have a model # or picture?
Drawn by the load. Voltage at a fixed value. Regulator output Vo to the op amp's negative input V-.
Adjusts the drive to Q1 such that V- is equal to the zener voltage Vz. The output voltage should be 3 x (1+10/5) = 9V. Run a simulation.
The output voltage at V(2)? Suppose you’re asked to design a 12V regulator. RF2 would you need with Vz = 3V?
Choose a new RF2 and test drive your circuit. How well does the regulator perform? Its output voltage.
Generates a 1A pulse starting at 10ms and ending at 20ms. Circuit by removing the "*" at the beginning of the IL statement.
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